A) \[{{S}_{N}}1\]mechanism
B) \[{{S}_{N}}2\]mechanism
C) any of (a) and (b)
D) None of the above
Correct Answer: A
Solution :
Tertiary halide preferentially undergo\[{{S}_{N}}1\] substitution as they give stable carbocation. \[{{H}_{3}}C-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \\ t-butyl\,\,chloride \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-Cl\xrightarrow[-Cl]{Slow}\underset{Carbocation}{\mathop{{{({{H}_{3}}C)}_{3}}{{C}^{+}}}}\,\xrightarrow[fast]{+O{{H}^{-}}}\]\[\underset{t-butyl\,\,alcohol}{\mathop{{{({{H}_{3}}C)}_{3}}COH}}\,\]
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