A) \[75%\]
B) \[87.5%\]
C) \[93.75%\]
D) \[92.5%\]
Correct Answer: C
Solution :
The amount of substance left after 4 half-lifes is\[N\]. \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}=100{{\left( \frac{1}{2} \right)}^{4}}=6.25%\] \[\therefore \]The fraction of element disintegrated \[={{N}_{0}}-N\] \[=100-6.25=93.75%\]
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