question_answer

The equivalent capacity between the points\[X\]and\[Y\]in the circuit with\[C=1\mu F\]is

A) \[2\mu F\]                         

B) \[3\mu F\]

C) \[1\mu F\]                                         

D) \[0.5\mu F\]

Correct Answer: A

Solution :

The circuit is shown in the figure. As points\[a\]and \[b\] are at same potential, so no charge flows through\[ab\]. Now two remaining capacitors are in parallel, hence                 \[{{C}_{eq}}=C+C=2C\]                        \[=2\times 1=2\mu F\]