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Punjab Medical Punjab - MET Solved Paper-2008

  • question_answer
    A body of mass \[2kg\] is thrown up vertically with kinetic energy of\[490J\]. If \[g=9.8\text{ }m/{{s}^{2}}\], the height at which the kinetic energy of the body becomes half of the original value, is

    A) \[50m\]                                               

    B) \[25m\]

    C) \[12.5m\]                           

    D) \[19.6m\]

    Correct Answer: C

    Solution :

    As body is thrown upwards with kinetic energy of \[490\,\,J\], so at maximum height it converts wholly to potential energy \[ie\],                 \[{{U}_{\max }}=490\,\,J\] Let at height\[h\], it becomes just half.                 \[mgh=\frac{{{U}_{\max }}}{2}\] or                 \[h=\frac{490}{2\times 2\times 9.8}=12.5\,\,m\]


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