A) ortho borate
B) meta borate
C) double oxide
D) tetra borate
Correct Answer: B
Solution :
In borax bead test the coloured metaborates are formed by transition metal salts. \[N{{a}_{2}}{{B}_{4}}{{O}_{7}}\cdot 10{{H}_{2}}O\xrightarrow[-10{{H}_{2}}O]{\Delta }N{{a}_{2}}{{B}_{4}}{{O}_{7}}\] \[\xrightarrow{\Delta }2NaB{{O}_{2}}+{{B}_{2}}{{O}_{3}}\] \[{{B}_{2}}{{O}_{3}}+CuO\xrightarrow{{}}\]\[\underset{cupric\,\,meta\,\,borate\,\,(bule\,\,head)}{\mathop{Cu{{(B{{O}_{2}})}_{2}}}}\,\]
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