A) Silicon exhibits 4 coordination number in its compounds
B) Bond energy of \[{{F}_{2}}\] is less than\[C{{l}_{2}}\]
C) Mn(III) oxidation state is more stable than Mn(II) in aqueous state
D) Elements of 15th group shows only+3 and +5 oxidation states
Correct Answer: B
Solution :
Bond energy of \[{{F}_{2}}\] is less than \[C{{l}_{2}}\] because in \[{{F}_{2}}\] molecule electron-electron repulsion of \[2p-\]orbital of two fluorine atom is maximum in comparison to this repulsion of \[3p-\]orbitals of two chlorine atom. So less amount of energy is required to break the bond of \[{{F}_{2}}\] in comparison to\[C{{l}_{2}}\].
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