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Punjab Medical Punjab - MET Solved Paper-2007

  • question_answer
    \[3A\xrightarrow{{}}2B\], rate of reactions\[+\frac{d[B]}{dt}\] is equal to

    A) \[-\frac{3}{2}\frac{d[A]}{dt}\]                   

    B) \[-\frac{2}{3}\frac{d[A]}{dt}\]

    C) \[-\frac{1}{3}\frac{d[A]}{dt}\]                   

    D) \[+2\frac{d[A]}{dt}\]

    Correct Answer: B

    Solution :

    For reaction,                 \[3A\xrightarrow{{}}2B\]                 \[Rate=-\frac{1}{3}\frac{d[A]}{dt}=+\frac{1}{2}\frac{d[B]}{dt}\] \[\therefore \]  \[+\frac{d[B]}{dt}=-\frac{2}{3}\frac{d[A]}{dt}\]


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