Punjab Medical Punjab - MET Solved Paper-2007

  • question_answer
    Solubility of\[M{{X}_{2}}-\]type electrolytes is\[0.5\times {{10}^{-4}}mol/L\] Then find out \[{{K}_{sp}}\] of electrolytes

    A) \[5\times {{10}^{-12}}\]               

    B) \[25\times {{10}^{-10}}\]

    C) \[1\times {{10}^{-13}}\]               

    D) \[5\times {{10}^{-13}}\]

    Correct Answer: D

    Solution :

    \[\underset{\begin{smallmatrix}  \text{Solubility}\,0.5\times {{10}^{-4}} \\  \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,M \end{smallmatrix}}{\mathop{M{{X}_{2}}}}\,\xrightarrow{{}}\underset{\begin{smallmatrix}  0.5\times {{10}^{-4}} \\  \,\,\,\,\,\,\,\,M \end{smallmatrix}}{\mathop{{{M}^{2+}}}}\,+\underset{\begin{smallmatrix}  2\times 0.5\times {{10}^{-4}} \\  \,\,\,\,\,\,\,\,\,\,M \end{smallmatrix}}{\mathop{2{{X}^{-}}}}\,\]       (on 100% ionisation) \[\therefore \]\[{{K}_{sp}}\]of\[M{{X}_{2}}=[{{M}^{2+}}]{{[{{X}^{-}}]}^{2}}\]                 \[=(0.5\times {{10}^{-4}}){{(1.0\times {{10}^{-4}})}^{2}}\]                 \[=0.5\times {{10}^{-12}}=5\times {{10}^{-13}}\]


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