Punjab Medical Punjab - MET Solved Paper-2007

  • question_answer
    The maximum intensity of fringes in Youngs experiment is J. If one of the slit is closed then the intensity at that place becomes\[{{I}_{0}}\]. Which of the following relation is true?

    A) \[I={{I}_{0}}\]

    B) \[I=2{{I}_{0}}\]

    C) \[I=4{{I}_{0}}\]

    D)  There is no relation between\[I\]and\[{{I}_{0}}\]

    Correct Answer: C

    Solution :

    Suppose slit widths are equal so they produces waves of equal intensity say\[I\]. Resultant intensity at any point\[{{I}_{R}}=4I{{\cos }^{2}}\phi \]where\[\phi \]is the phase difference between the waves at the point of observation. For maximum intensity,\[\phi ={{0}^{o}}\]                 \[{{I}_{\max }}=4I=I\]                                     ... (i) If one of slit is closed, resultant intensity at the same point will be\[I\] only ie \[I={{I}_{0}}\]... (ii) Comparing Eqs. (i) and (ii) we get                 \[I=4{{I}_{0}}\]


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