A) \[1.82\times {{10}^{-10}}%\]
B) \[1.85\times {{10}^{-15}}%\]
C) \[1.85\times {{10}^{-17}}%\]
D) \[1.85\times {{10}^{-18}}%\]
Correct Answer: D
Solution :
Mass equivalent to \[1022J\] of energy \[m=\frac{E}{{{c}^{2}}}={{10}^{22}}=\frac{{{10}^{22}}}{{{(3\times {{10}^{8}})}^{2}}}=\frac{{{10}^{6}}}{9}kg\] Percentage increase in mass \[=\frac{{{10}^{6}}}{9}\times \frac{100}{6\times {{10}^{24}}}=1.85\times {{10}^{-18}}%\]
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