Punjab Medical Punjab - MET Solved Paper-2007

  • question_answer
    If the power factor changes from\[\frac{1}{2}\]to\[\frac{1}{4}\], then what is the increase in impedance in\[AC\]?

    A) \[20%\]                               

    B) \[50%\]

    C) \[25%\]                               

    D) \[100%\]

    Correct Answer: D

    Solution :

    Power factor is\[\cos \phi =\frac{R}{Z}\] If\[R\]is constant, then                 \[\cos \phi \propto \frac{1}{Z}\] \[\therefore \]  \[\frac{{{Z}_{1}}}{{{Z}_{2}}}=\frac{\cos {{\phi }_{1}}}{\cos {{\phi }_{2}}}=\frac{1/4}{1/2}=\frac{1}{2}\] \[\Rightarrow \]               \[{{Z}_{2}}=2{{Z}_{1}}\] \[\therefore \]Percentage change\[=\frac{2{{Z}_{1}}-{{Z}_{1}}}{{{Z}_{1}}}\times 100\]                 \[=100%\]


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