A) \[4\times {{10}^{-19}}V\text{-}s\]
B) \[0.25\times {{10}^{-15}}V\text{-}s\]
C) \[4\times {{10}^{-15}}V\text{-}s\]
D) \[4\times {{10}^{-8}}V\text{-}s\]
Correct Answer: C
Solution :
According to photoelectric equation \[eV=\frac{hc}{\lambda }-{{W}_{0}}\] \[0.5e=\frac{hc}{6\times {{10}^{-7}}}-{{W}_{0}}\] \[\Rightarrow \] \[0.5=\frac{h}{e}\times \frac{c}{6\times {{10}^{-7}}}-\frac{{{W}_{0}}}{e}\] ? (i) Similarly, \[1.5=\frac{h}{e}\times \frac{c}{4\times {{10}^{-7}}}-\frac{{{W}_{0}}}{e}\] ? (ii) From Eqs. (i) and (ii), \[1=\frac{h}{e}\times \frac{c}{4\times {{10}^{-7}}}\left( \frac{1}{4}-\frac{1}{6} \right)\] \[\Rightarrow \] \[\frac{h}{e}=\frac{12\times {{10}^{-7}}}{3\times {{10}^{8}}}=4\times {{10}^{-15}}\]
You need to login to perform this action.
You will be redirected in
3 sec
