A) \[45cm\]
B) \[30cm\]
C) \[40cm\]
D) \[25cm\]
Correct Answer: C
Solution :
Using relation\[v=n\lambda \] \[\lambda =\frac{v}{n}=\frac{340}{340}=1\,\,m\] If length of resonance columns are\[{{l}_{1}},\,\,{{l}_{2}}\]and\[{{l}_{3}}\], then\[{{l}_{1}}=\frac{\lambda }{4}=\frac{l}{4}m=25\,\,cm\](for first resonance) \[{{l}_{2}}=3\frac{\lambda }{4}=\frac{3}{4}m=75cm\] (for second resonance) \[{{l}_{3}}=\frac{5\lambda }{4}=\frac{5}{4}m=125\,\,cm\] (for third resonance) This case of third resonance is impossible because total length of the tube is\[120cm\]. So, minimum height of water \[=120-75=45cm\]
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