A) \[{{101.04}^{o}}C\]
B) \[{{100.26}^{o}}C\]
C) \[{{100.52}^{o}}C\]
D) \[{{99.74}^{o}}C\]
Correct Answer: A
Solution :
\[\Delta {{T}_{b}}={{k}_{b}}t\times \]molality for dilute solution molarity = molality = 2 (given) and\[{{k}_{b}}=0.52\](given) \[\therefore \] \[\Delta {{T}_{b}}=0.52\times 2={{1.04}^{o}}C\] Now, \[\Delta {{T}_{b}}=\]B.P. of solution - B.P. of solvent (i. e. \[{{H}_{2}}O\]) \[\therefore \]B.P. of solution\[=\Delta {{T}_{b}}+B.P.\,\,of\,\,{{H}_{2}}O\] \[=1.04+100={{101.4}^{o}}C\]
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