A) \[6.135\times {{10}^{-29}}kg\]
B) \[3.60\times {{10}^{-29}}kg\]
C) \[6.135\times {{10}^{-33}}kg\]
D) \[3.60\times {{10}^{-27}}kg\]
Correct Answer: C
Solution :
We know that \[E=m{{c}^{2}}=\frac{hc}{\lambda }\] \[\therefore \] \[\lambda =\frac{h}{mc}\] or \[m=\frac{h}{\lambda c}\] Where, \[\lambda =\]wavelength of photon \[h=\] plancks constant \[m=\] mass of photon \[c=\] velocity of light Given, \[\lambda =3.6\overset{\text{o}}{\mathop{\text{A}}}\,=3.6\times {{10}^{-10}}m\] \[\therefore \] \[m=\frac{6.62\times {{10}^{-34}}}{3.6\times {{10}^{-10}}\times 3\times {{10}^{8}}}\] \[=6.135\times {{10}^{-33}}kg\]
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