A) \[5\times {{10}^{-8}}\]
B) \[5\times {{10}^{-9}}\]
C) \[5\times {{10}^{-10}}\]
D) \[4\times {{10}^{-10}}\]
Correct Answer: C
Solution :
Hydrolysis constant of sodium acetate \[{{K}_{h}}=\frac{{{K}_{w}}}{{{K}_{a}}}\] \[\because \] \[{{K}_{w}}={{10}^{-14}}\]and\[{{K}_{a}}=2\times {{10}^{-5}}\](given) \[\therefore \] \[{{K}_{h}}=\frac{{{10}^{-14}}}{2\times {{10}^{-5}}}=\frac{10}{2}\times {{10}^{-10}}\] \[=5\times {{10}^{-10}}\]
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