A) \[1%\]
B) \[1/3%\]
C) \[3%\]
D) \[10%\]
Correct Answer: C
Solution :
Let \[R\] be the radius of a sphere. Volume of sphere\[=\frac{4}{3}\pi {{R}^{3}}\] Taking log on both sides we have \[\log V=\log \frac{4}{3}\pi +\log {{R}^{3}}\] \[\log V=\frac{4}{3}\pi +3\log R\] In order to obtain charge in volume, we differentiate both sides. \[\therefore \] \[\frac{\Delta V}{V}=\frac{3\Delta R}{R}\] \[\therefore \]Percentage charge in volume\[=3\times \] percentage charge in radius \[=3\times 1%=3%\]
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