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Punjab Medical Punjab - MET Solved Paper-2006

  • question_answer
    For a wire of length Z, maximum change in length under stress condition is 2 mm. What is the charge in length under same conditions when length of wire is halved?

    A) \[1mm\]                             

    B) \[2mm\]

    C) \[4mm\]                             

    D) \[8mm\]

    Correct Answer: A

    Solution :

    \[Y=\frac{longitudinal\,\,stress}{longitudinal\,\,strain}\]                 \[Y=\frac{F/A}{\Delta l/L}\] where \[F\] is force, \[A\]is area, \[\Delta l\]is change is length and \[L\] is original length. First case             \[Y=\frac{F/A}{2/L}\]                      ? (i) Second case       \[Y=\frac{F/A}{\Delta l/L/2}\]                     ? (ii) Equating Eqs. (1) and (2), we get                 \[\frac{L}{2}=\frac{L/2}{\Delta l}\] \[\Rightarrow \]               \[\Delta l=1mm\]


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