question_answer

The potentials of the two plates of capacitors are \[+10V\] and\[-10V\]. The charge on one of the plates is\[40\,\,C\]. The capacitance of the capacitor is:

A) \[2\,\,F\]                                            

B) \[4\,\,F\]

C) \[0.5\,\,F\]                         

D) \[0.25\,\,F\]

Correct Answer: A

Solution :

A capacitor is an arrangement which can store sufficient quantity of charge. Suppose, on given a charge \[q\] to a conductor, the electric potential of the conductor becomes \[V\], Then, capacitance of capacitor is The potential difference across the parallel plate capacitor is\[10V-(-10V)=20V\] \[\therefore \]Capacitance\[C=\frac{Q}{V}=\frac{40}{20}=2F\]