A) carbon
B) boron
C) oxygen
D) nitrogen
Correct Answer: D
Solution :
Electronic configuration of carbon\[=1{{s}^{2}},\,\,2{{s}^{2}},\,\,2{{p}^{2}}\] Electronic configuration of boron\[=1{{s}^{2}},\,\,2{{s}^{2}},\,\,2{{p}^{1}}\] Electronic configuration of oxygen\[=1{{s}^{2}},\,\,2{{s}^{2}},\,\,2{{p}^{4}}\] Electronic configuration of nitrogen\[=1{{s}^{2}},\,\,2{{s}^{2}},\,\,2{{p}^{3}}\] Among these nitrogen has the highest ionization potential because in nitrogen atom, the outer most electron is present in half filled \[2{{p}_{z}}\] sub shell. Which is a stable electronic configuration.
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