| (i)\[M{{n}^{2+}}\] |
| (ii)\[Mn{{O}_{2}}\] |
| (iii)\[KMn{{O}_{4}}\] |
| (iv)\[{{K}_{2}}Mn{{O}_{4}}\] |
A) (i) > (ii) > (iii) > (iv)
B) (i) < (ii) < (iv) < (iii)
C) (ii) < (iii) < (i) < (iv)
D) (iii) > (i) > (iv) > (ii)
Correct Answer: B
Solution :
The oxidation number of\[Mn\]in\[M{{n}^{2+}}\] is\[+2\] Let the oxidation number of \[Mn\] in\[Mn{{O}_{2}}\] be\[x\] \[x+2(-2)=0\] \[x-4=0\] \[x=+4\] Let the oxidation number of \[Mn\] in \[KMn{{O}_{4}}\] be\[x\] \[(+1)+x+4(-2)=0\] \[1+x-8=0\] \[x-7=0\] \[x=+7\] Let the oxidation number of \[Mn\] in\[KMn{{O}_{4}}\]be \[x\] \[2(+1)+x+4(-2)=0\] \[+2+x-8=0\] \[x-6=0\] \[x=+6\] thus arrange the oxidation number in increasing order \[=M{{n}^{2+}}<Mn{{O}_{2}}<{{K}_{2}}Mn{{O}_{4}}<KMn{{O}_{4}}\] +2 +4 +6 +7 i.e., (i) < (ii) < (iv) < (iii)
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