A) \[[M{{L}^{2}}{{T}^{-1}}]\]
B) \[[ML{{T}^{-2}}]\]
C) \[[M{{L}^{-2}}T]\]
D) \[[M{{L}^{-1}}{{T}^{2}}]\]
Correct Answer: A
Solution :
Unit of Plancks constant\[=joule-\sec \] Dimensions of Plancks constant \[=[M{{L}^{2}}{{T}^{-2}}][T]=[M{{L}^{2}}{{T}^{-1}}]\]
You need to login to perform this action.
You will be redirected in
3 sec
