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Punjab Medical Punjab - MET Solved Paper-2005

  • question_answer
    The current in a coil decreases from \[1A\] to \[0.2A\]in\[10\sec \]. The coefficient of self-inductance, if induced emf is \[0.4volt\], is:

    A) \[5H\]                                  

    B) \[3H\]

    C) \[4H\]                                  

    D) \[2H\]

    Correct Answer: A

    Solution :

    Induced emf\[e=-L\frac{\Delta i}{\Delta t}\]                 \[0.4=-L\frac{(0.2-1)}{10}\]                 \[0.4=L\times \frac{0.8}{10}\]                 \[L=\frac{0.4\times 10}{0.8}\]                                 \[=5H\]


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