Punjab Medical Punjab - MET Solved Paper-2005

  • question_answer
    The standard reduction potential \[E{}^\circ \] for the half reactions are as                 \[Zn\xrightarrow{{}}Z{{n}^{++}}+2{{e}^{-}},\,\,E{}^\circ =0.76V\]                 \[Cu\xrightarrow{{}}C{{u}^{++}}+2{{e}^{-}},\,\,E{}^\circ =0.34V\] The e.m.f. for the cell reaction                 \[Zn+C{{u}^{2+}}\xrightarrow{{}}Z{{n}^{2+}}+Cu\]

    A) \[0.42V\]                            

    B) \[-0.42V\]

    C) \[-1.1V\]                             

    D) \[1.1V\]

    Correct Answer: D

    Solution :

    \[E_{cell}^{\text{o}}=E_{cathode}^{\text{o}}-E_{anode}^{\text{o}}\]                 \[=0.34V-(-0.76V)\]                 \[=0.34+0.76V=1.1V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner