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Punjab Medical Punjab - MET Solved Paper-2004

  • question_answer
    If\[\vec{A}\times \vec{B}|=|\vec{A}\bullet \vec{B}|\]then the angle between \[\vec{A}\] and \[\vec{B}\] will be:

    A) \[{{90}^{o}}\]                                    

    B) \[{{60}^{o}}\]

    C) \[{{45}^{o}}\]                                    

    D) \[{{30}^{o}}\]

    Correct Answer: C

    Solution :

    The moduli of cross and dot product of vector \[\vec{A}\]and \[\vec{B}\] are \[AB\] \[\sin \theta \] and \[AB\cos \theta \] respectively. Therefore, the given condition,                 \[AB\sin \theta =AB\cos \theta \] or            \[\tan \theta =1\]or\[\theta ={{45}^{o}}\]


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