A) \[3.6\,\,V\]
B) \[10.2\,\,V\]
C) \[3.2\,\,V\]
D) \[13.6\,\,V\]
Correct Answer: B
Solution :
Minimum excitation energy \[\Delta {{E}_{1}}=Rhc\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right)\] \[=13.6\times \frac{3}{4}=10.2eV\] Therefore, minimum excitations potential is \[=10.2\,\,V\]
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