Punjab Medical Punjab - MET Solved Paper-2004

  • question_answer
    In Bohrs model the atomic radius of the first orbit is\[{{r}_{0}}\], the radius of the third orbit will be:

    A) \[9{{r}_{0}}\]                                     

    B) \[3{{r}_{0}}\]

    C) \[{{r}_{0}}\]                                       

    D) \[\frac{{{r}_{0}}}{3}\]

    Correct Answer: A

    Solution :

    Here: Radius of first orbit\[={{r}_{0}}\] The radius of \[n\]the orbit is given by,                 \[{{r}_{n}}=\frac{{{\varepsilon }_{0}}{{h}^{2}}}{\pi m{{Z}_{e}}^{2}}\times {{n}^{2}}\propto {{n}^{2}}\] Hence,  \[\frac{{{r}_{1}}}{{{r}_{2}}}={{\left( \frac{{{n}_{1}}}{{{n}_{2}}} \right)}^{2}}=\frac{1}{9}\] or            \[{{r}_{3}}=9{{r}_{1}}=9{{r}_{0}}\](where \[{{r}_{3}}\] is the radius of 3rd orbit)


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