A) Ethane
B) Ethene
C) Ethyne
D) All of these
Correct Answer: B
Solution :
This is an example of Kolbes electrolysis. Ethylene is obtained on electrolysis of potassium succinate. \[\begin{align} & C{{H}_{2}}COOK \\ & | \\ & C{{H}_{2}}COOK \\ \end{align}\] \[\xrightarrow{electrolysis}\]\[\begin{align} & C{{H}_{2}}CO{{O}^{-}} \\ & | \\ & C{{H}_{2}}CO{{O}^{-}}+2{{K}^{+}} \\ \end{align}\] At anode \[\begin{align} & C{{H}_{2}}CO{{O}^{-}} \\ & | \\ & C{{H}_{2}}CO{{O}^{-}} \\ \end{align}\]\[\xrightarrow{-2{{e}^{-}}}\]\[\begin{align} & C{{H}_{2}}CO{{O}^{\centerdot }} \\ & | \\ & C{{H}_{2}}CO{{O}^{\centerdot }} \\ \end{align}\]\[\xrightarrow{-2C{{O}_{2}}}\]\[\begin{align} & CH_{2}^{\centerdot } \\ & | \\ & CH_{2}^{\centerdot } \\ \end{align}\]\[\xrightarrow{{}}\]\[\begin{align} & C{{H}_{2}} \\ & || \\ & \underset{Ethene}{\mathop{C{{H}_{2}}}}\, \\ \end{align}\]
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