A) \[1.66\times {{10}^{-34}}\,\,nm\]
B) \[8.28\times {{10}^{-32}}\,\,nm\]
C) \[8.28\times {{10}^{-25}}\,\,nm\]
D) \[1.66\times {{10}^{-24}}\,\,nm\]
Correct Answer: C
Solution :
From de-Broglie equation, \[\lambda =\frac{h}{mv}\] \[\therefore \] \[\lambda =\frac{6.626\times {{10}^{-34}}j\text{-}s}{40\times {{10}^{-3}}kg\times 20.0m{{s}^{-1}}}\] \[=8.28\times {{10}^{-34}}m\] \[=8.28\times {{10}^{-34}}\times {{10}^{9}}nm\] \[=8.28\times {{10}^{-25}}nm\]
You need to login to perform this action.
You will be redirected in
3 sec
