2. Solved Papers
  3. Punjab Medical

Punjab Medical Punjab - MET Solved Paper-2003

  • question_answer
    A Carnots engine works between temperature \[{{72}^{o}}C\] and\[{{27}^{o}}C\], the efficiency of the engine is:

    A) \[100%\]                             

    B) \[90%\]

    C) \[35%\]                               

    D) \[70%\]

    Correct Answer: D

    Solution :

    Using the relation for the efficiency of Carnots engine, we have                 \[\eta =\left( 1-\frac{{{T}_{2}}}{{{T}_{1}}} \right)\times 100\] Here:     \[{{T}_{2}}=273+27=300\,\,K\]                 \[{{T}_{1}}=273+727=1000\,\,K\]                 \[\eta =\left( 1-\frac{300}{1000} \right)\times 100=70%\]


You need to login to perform this action.
You will be redirected in 3 sec spinner