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Punjab Medical Punjab - MET Solved Paper-2003

  • question_answer
    When a resistance of \[\text{a}\] \[\Omega \] is connected at the ends of a battery, its potential difference decreases from \[40\,\,V\] to\[30\,\,V\]. The internal resistance of the battery is:

    A) \[3\,\,\Omega \]                                             

    B) \[6\,\,\Omega \]

    C) \[1.5\,\,\Omega \]                         

    D) \[4\,\,\Omega \]

    Correct Answer: A

    Solution :

    \[E=40\,\,V,\,\,V=30\,\,V,\,\,r=a\,\,\Omega \] Internal resistance                 \[r=\left( \frac{E}{V}-1 \right)R\]                    \[=\left( \frac{40}{30}-1 \right)9\]                    \[=\frac{1}{3}\times 9=3\,\,\Omega \]


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