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Punjab Medical Punjab - MET Solved Paper-2003

  • question_answer
    The resistance of a galvanometer is\[50\Omega \]. When \[0.01\,\,A\] current flows in it, full scale deflection is obtained in galvanometer, the resistance of shunt connected to convert galvanometer into an ammeter of range\[5\,\,A\], will be:

    A) \[0.1\Omega \]                

    B) \[0.2\Omega \]

    C) \[0.3\Omega \]                

    D) \[0.4\Omega \]

    Correct Answer: A

    Solution :

    Here:\[{{I}_{g}}=0.01\,\,A,\,\,G=50\Omega \] To convert the galvanometer in to an ammeter of range of\[5A\], a low resistance is to be connected in parallel with coil of galvanometer.                 \[S=\frac{ig\times G}{i-{{i}_{g}}}\]                    \[=\frac{0.01\times 50}{5-0.01}=\frac{0.5}{4.99}\]                    \[=0.1\,\,\Omega \]


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