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Punjab Medical Punjab - MET Solved Paper-2003

  • question_answer
    If the current \[30\,\,A\] flowing in the primary coil is made zero is\[0.1\,\,\sec \]. The emf induced in the secondary coil is\[1.5\,\,volt\]. The mutual inductance between the coil is:

    A) \[0.05H\]                            

    B) \[1.05H\]

    C) \[0.1H\]                               

    D) \[0.2H\]

    Correct Answer: A

    Solution :

    Here:\[e=1.5\,\,volt\]\[\Delta i=0-3.0=-3A,\,\,\Delta t=0.1\,\,\sec \] Now the emf induced in secondary coil                 \[e=\frac{M\Delta i}{\Delta t}\](numerically) or            \[1.5=\frac{M\times 3}{0.1}\] or            \[M=\frac{1.5\times 0.1}{3}=0.05\,\,H\]


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