A) \[2.24\,\,litre\]
B) \[4.48\,\,litre\]
C) \[20\,\,litre\]
D) \[22.4\,\,litre\]
Correct Answer: B
Solution :
\[\underset{\begin{smallmatrix} (40+12+3\times 16) \\ \,\,\,\,\,\,\,\,\,\,\,\,=100 \end{smallmatrix}}{\mathop{CaC{{O}_{3}}}}\,\xrightarrow{\Delta }CaO+\underset{22.4\,\,litre}{\mathop{C{{O}_{2}}}}\,\] \[\because \,\,100\,\,g\,\,CaC{{O}_{3}}\], on decomposition, gives\[=22.4\,\,litre\,\,C{{O}_{2}}\]at STP \[\therefore \,\,20\,\,g\,\,CaC{{O}_{3}}\], on decomposition, will give \[=\frac{22.4\times 20}{100}\] \[=4.48\,\,litre\,\,C{{O}_{2}}\]at STP
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