A) \[2\times {{10}^{-5}}wb/{{m}^{2}}\]
B) \[9\times {{10}^{-5}}wb/{{m}^{2}}\]
C) \[8\times {{10}^{-5}}wb/{{m}^{2}}\]
D) \[6\times {{10}^{-5}}wb/{{m}^{2}}\]
Correct Answer: A
Solution :
Here:\[i=20\,\,A,\,\,r=10\,\,cm=0.1\,\,m\] Intensity of magnetic field produced due to straight current carrying wire is \[B=\frac{{{\mu }_{0}}}{4\pi }\times \frac{2i}{r}\] \[={{10}^{-7}}\times \frac{2\times 20}{0.1}\] \[=4\times {{10}^{-5}}wb/{{m}^{2}}\]
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