Punjab Medical Punjab - MET Solved Paper-2003

  • question_answer
    The peak value of alternating current is \[5\sqrt{2}\] ampere. The mean square value of current will be:

    A) \[5\,\,A\]                                            

    B) \[2.5\,\,A\]

    C) \[5\sqrt{2}\]                                      

    D)  none of these

    Correct Answer: A

    Solution :

    Here:\[{{I}_{0}}=5\sqrt{2}A\] Root mean square value of current                 \[{{I}_{rms}}=\frac{{{I}_{0}}}{\sqrt{2}}=\frac{5\sqrt{2}}{\sqrt{2}}=5\,\,A\]


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