2. Solved Papers
  3. Punjab Medical

Punjab Medical Punjab - MET Solved Paper-2003

  • question_answer
    The work done in pulling up a block of wood weighing \[2\,\,kN\] for a length of \[10\,\,m\] on a smooth plane inclined at an angle of \[{{15}^{o}}\] with the horizontal is:

    A) \[9.82\,\,kJ\]                     

    B) \[89\,\,kJ\]

    C) \[4.35\,\,kJ\]                     

    D) \[5.17\,\,kJ\]

    Correct Answer: D

    Solution :

    Here: weight of block\[w=2kN\], Distance\[d=10\,\,m\] Angle of inclination on the plane\[\alpha ={{15}^{o}}\] The block will be pulled up on a smooth Plane Hence, force of resistance due to inclination \[F=w\sin \alpha =2\times {{10}^{3}}\sin {{15}^{o}}\]                 \[=2\times {{10}^{3}}\times 0.2588\]                 \[=0.5176\,\,kN\] Now work done, \[W=Fd=0.5176\times {{10}^{3}}\times 10\]                 \[=5.17\,\,kN\]


You need to login to perform this action.
You will be redirected in 3 sec spinner