Punjab Medical Punjab - MET Solved Paper-2001

  • question_answer
    A body of mass \[40\,\,kg\] having velocity \[4\,\,m/s\] colloids with another body of mass 60kg having velocity\[2\,\,m/s\]. If the collision is inelastic, then loss in kinetic energy will be

    A) \[440\,\,\text{J}\]                           

    B) \[392\,\,\text{J}\]

    C) \[48\,\,\text{J}\]                                             

    D) \[144\,\,\text{J}\]

    Correct Answer: C

    Solution :

    Here: Mass of first body\[{{m}_{1}}=40\,\,kg\] Speed of first body\[{{v}_{1}}=4\,\,m/s\] Mass of second body\[{{m}_{2}}=60\,\,kg\] Speed of second body\[{{v}_{2}}=2\,\,m/s\] When collision is inelastic, then the loss in kinetic energy is given by                 \[=\frac{1}{2}\left( \frac{{{m}_{1}}{{m}_{2}}}{{{m}_{1}}+{{m}_{2}}} \right){{({{v}_{1}}-{{v}_{2}})}^{2}}\]                 \[=\frac{1}{2}\left( \frac{40\times 60}{40+60} \right)\times {{(4-2)}^{2}}\]                 \[=\frac{1}{2}\times \frac{2400}{100}\times 4=48\,\,J\]


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