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Punjab Medical Punjab - MET Solved Paper-2001

  • question_answer
    A battery of \[12\,\,V\] and an internal resistance of \[0.80\] is connected to 3 resistors as shown in the fig. The current ( in the circuit is

    A) \[2.3\,\,A\]                        

    B) \[4.0\,\,A\]

    C) \[2.0\,\,A\]                        

    D) \[1.33\,\,A\]

    Correct Answer: C

    Solution :

    Using the relation for current                 \[i=\frac{E}{R+r}\]                                           ? (1) But the equivalent resistance in the upper arm is given by as                 \[{{R}_{equivalent}}=4\Omega +\frac{2\times 3}{2+3}\Omega \]                 \[{{R}_{q}}=4+\frac{6}{5}=\frac{26}{5}=5.2\] Now equation (1) we get                 \[i=\frac{12}{5.2+0.8}=\frac{12}{6}=2\,\,amp\]


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