A) \[{{H}_{2}}O\]
B) \[{{H}_{2}}S\]
C) \[N{{H}_{3}}\]
D) \[C{{H}_{4}}\]
Correct Answer: B
Solution :
Due to tetrahedral hybridisation and two lone pairs of electrons in \[{{H}_{2}}S\] and\[{{H}_{2}}O\]bond angle contracts. The contraction is more in\[{{H}_{2}}S\]
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