Punjab Medical Punjab - MET Solved Paper-2001

  • question_answer
    What is \[\Delta n\] for combustion of 1 mole of benzene, when both the reactants and the products are gas at\[298\,\,K\]

    A) \[0\]                                     

    B) \[3/2\]

    C) \[-3/2\]               

    D) \[1/2\]

    Correct Answer: D

    Solution :

    \[{{C}_{6}}{{H}_{6}}(g)+\frac{15}{2}{{O}_{2}}(g)\xrightarrow{{}}6C{{O}_{2}}(g)\]\[+3{{H}_{2}}O(g)\]                 \[\Delta n=(6+3)-\left( 1+\frac{15}{2} \right)=+1/2\].


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