A) \[6.75\times {{10}^{12}}Hz\]
B) \[6.75\times {{10}^{14}}Hz\]
C) \[6.75\times {{10}^{13}}Hz\]
D) None of these
Correct Answer: C
Solution :
Using the relation we have \[\frac{1}{\lambda }={{R}_{H}}\left( \frac{1}{{{4}^{2}}}-\frac{1}{{{5}^{2}}} \right)\] \[v=\frac{c}{\lambda }=c{{R}_{H}}\left[ \frac{1}{16}-\frac{1}{25} \right]\] \[=3\times {{10}^{8}}\times {{10}^{7}}\times 0.0225\] \[=6.75\times {{10}^{13}}\,\,Hz\]
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