A) \[4\times {{10}^{-11}}s\]
B) \[2\times {{10}^{-11}}s\]
C) \[16\times {{10}^{-11}}s\]
D) \[8\times {{10}^{-11}}s\]
Correct Answer: A
Solution :
Using the relation Time taken\[\text{=}\frac{\text{distance}}{\text{velocity}}\] \[\text{=}\frac{\text{optical}\,\,\text{path}}{\text{velocity}\,\,\text{of}\,\,\text{light}}\] \[i.e.\,\,t=\frac{\mu t}{v}=\frac{3\times 4\times {{10}^{-3}}}{3\times {{10}^{8}}}\] \[=4\times {{10}^{-11}}\sec \]
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