question_answer

Four capacitors are connected in circuit as shown in the given figure. The effective capacitance between points \[A\] and \[B\] will be

A) \[4\,\,\mu F\]                   

B) \[18\,\,\mu F\]

C) \[\frac{28}{9}\,\,\mu F\]                              

D) \[5\,\,\mu F\]

Correct Answer: D

Solution :

The circuit which is given that can be rearranged as Now the resultant capacitance between \[\mathbf{A}\] and \[\mathbf{B}\] is given by                 \[{{C}_{AB}}=\frac{4\times 12}{4+12}=2=3+2=5\mu F\]