Punjab Medical Punjab - MET Solved Paper-2001

  • question_answer
    A block slides down an inclined plane making   an angle \[\theta ={{30}^{o}}\] with the horizontal with an acceleration\[\frac{g}{4}\], then coefficient of frictions will be

    A) \[\frac{1}{4}\left( \frac{\sqrt{3}}{2} \right)\]                       

    B) \[\frac{1}{4}-\frac{\sqrt{3}}{2}\]

    C) \[\frac{1}{2\sqrt{3}}\]                                   

    D) \[2\sqrt{3}\]

    Correct Answer: C

    Solution :

    Acceleration is given by as                 \[a=g\sin \theta -\mu \,\,g\,\,\cos \theta \] or            \[\frac{g}{4}=g(\sin \theta -\mu \,\,\cos \theta )\] or            \[\frac{1}{4}=(\sin {{30}^{o}}-\mu \,\,\cos \,\,{{30}^{o}})\] or            \[\frac{1}{4}=\frac{1}{2}-\frac{\mu \sqrt{3}}{2}\] or            \[\frac{\mu \sqrt{3}}{2}=\frac{1}{2}-\frac{1}{4}=\frac{1}{4}\]                 \[\mu =\frac{1}{2\sqrt{3}}\]


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