A) \[{{30}^{o}}\]
B) \[{{45}^{o}}\]
C) \[{{60}^{o}}\]
D) \[{{90}^{o}}\]
Correct Answer: A
Solution :
Using the relation \[R=\frac{{{u}^{2}}\sin 2\,\,\theta }{g}\]and\[H=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2\,\,g}\] Given\[\frac{{{u}^{2}}\sin 2\theta }{g}=4\sqrt{3}\left( \frac{{{u}^{2}}{{\sin }^{2}}\theta }{2\,\,g} \right)\] \[2\sin \theta \cos \theta =\frac{4\sqrt{3}{{\sin }^{2}}\theta }{2}\] \[\frac{1}{\sqrt{3}}=\frac{\sin \theta }{\cos \theta }=\tan \theta \]or\[\tan \theta =\frac{1}{\sqrt{3}}\] Hence,\[\theta ={{30}^{o}}\]
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