A) \[1{{s}^{2}},\,\,2{{s}^{2}}2{{p}^{6}}\]
B) \[1{{s}^{2}},\,\,2{{s}^{2}}2{{p}^{6}},\,\,3{{s}^{1}}\]
C) \[1{{s}^{2}},\,\,2{{s}^{2}}2{{p}^{5}}\]
D) \[1{{s}^{2}},\,\,2{{s}^{2}}2{{p}^{3}}\]
Correct Answer: B
Solution :
Electronic configuration of alkali metal is\[(1{{s}^{2}},\,\,2{{s}^{2}}2{{p}^{6}}3{{s}^{1}})\]. Thus it has the lowest value of ionization energy.
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