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Punjab Medical Punjab - MET Solved Paper-1999

  • question_answer
    In\[C{{H}_{2}}C{{l}_{2}}\], the oxidation number of \[C\] is

    A) \[+2\]                                   

    B) \[-4\]

    C) \[0\]                                     

    D) \[+4\]

    Correct Answer: C

    Solution :

    Let \[x\] be the oxidation number of \[C\] in\[C{{H}_{2}}C{{l}_{2}}\]\[x+2\times 1+2\times (-1)=0\]\[x=0\]


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