A) \[mole.litr{{e}^{-1}}\]
B) \[mol{{e}^{2}}.litr{{e}^{-2}}\]
C) \[litre.mol{{e}^{-1}}\]
D) \[litr{{e}^{-1}}.mol{{e}^{-1}}\]
Correct Answer: C
Solution :
We know that dimension of equilibrium constant for the gas\[(K)=\frac{[{{C}_{2}}{{H}_{6}}]}{[{{C}_{2}}{{H}_{4}}][{{H}_{2}}]}\] \[=\frac{mole.litr{{e}^{-1}}}{(mole.litr{{e}^{-1}}).(mole.litr{{e}^{-1}})}\]\[=\frac{1}{mole.litr{{e}^{-1}}}=litre.mol{{e}^{-1}}\]
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