A) \[s{{p}^{2}}\] hybridized
B) \[s{{p}^{3}}d\] hybridized
C) \[sp\]hybridized
D) \[s{{p}^{3}}\]hybridized
Correct Answer: A
Solution :
\[{{H}_{3}}{{C}^{+}}\]has\[s{{p}^{2}}\]hybridized carbon atom.
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